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13131033045547 is a prime number
BaseRepresentation
bin1011111100010100111010…
…0011110110101000101011
31201111022111021021220222111
42333011032203312220223
53210114323424424142
643532151401303151
72523454145201344
oct277051643665053
951438437256874
1013131033045547
11420292691327a
121580a70494ab7
1374333589a3b1
1433578c7a10cb
1517b87d057e17
hexbf14e8f6a2b

13131033045547 has 2 divisors, whose sum is σ = 13131033045548. Its totient is φ = 13131033045546.

The previous prime is 13131033045457. The next prime is 13131033045617. The reversal of 13131033045547 is 74554033013131.

Together with previous prime (13131033045457) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13131033045547 - 239 = 12581277231659 is a prime.

It is not a weakly prime, because it can be changed into another prime (13131033045047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565516522773 + 6565516522774.

It is an arithmetic number, because the mean of its divisors is an integer number (6565516522774).

Almost surely, 213131033045547 is an apocalyptic number.

13131033045547 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131033045547 is an equidigital number, since it uses as much as digits as its factorization.

13131033045547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 226800, while the sum is 40.

Adding to 13131033045547 its reverse (74554033013131), we get a palindrome (87685066058678).

The spelling of 13131033045547 in words is "thirteen trillion, one hundred thirty-one billion, thirty-three million, forty-five thousand, five hundred forty-seven".