Base | Representation |
---|---|
bin | 1011111100010100111010… |
… | …0011110110101000101111 |
3 | 1201111022111021021220222122 |
4 | 2333011032203312220233 |
5 | 3210114323424424201 |
6 | 43532151401303155 |
7 | 2523454145201351 |
oct | 277051643665057 |
9 | 51438437256878 |
10 | 13131033045551 |
11 | 4202926913283 |
12 | 1580a70494abb |
13 | 74333589a3b5 |
14 | 33578c7a10d1 |
15 | 17b87d057e1b |
hex | bf14e8f6a2f |
13131033045551 has 4 divisors (see below), whose sum is σ = 13131049138152. Its totient is φ = 13131016952952.
The previous prime is 13131033045547. The next prime is 13131033045617. The reversal of 13131033045551 is 15554033013131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13131033045551 - 22 = 13131033045547 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13131033042551) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6753065 + ... + 8477378.
It is an arithmetic number, because the mean of its divisors is an integer number (3282762284538).
Almost surely, 213131033045551 is an apocalyptic number.
13131033045551 is a deficient number, since it is larger than the sum of its proper divisors (16092601).
13131033045551 is an equidigital number, since it uses as much as digits as its factorization.
13131033045551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16092600.
The product of its (nonzero) digits is 40500, while the sum is 35.
Adding to 13131033045551 its reverse (15554033013131), we get a palindrome (28685066058682).
The spelling of 13131033045551 in words is "thirteen trillion, one hundred thirty-one billion, thirty-three million, forty-five thousand, five hundred fifty-one".
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