13131044111 has 4 divisors (see below), whose sum is σ = 13327029912. Its totient is φ = 12935058312.

The previous prime is 13131044081. The next prime is 13131044119. The reversal of 13131044111 is 11144013131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11144013131 = 70237 ⋅158663.

It is a cyclic number.

It is not a de Polignac number, because 13131044111 - 2²² = 13126849807 is a prime.

It is a super-3 number, since 3×13131044111³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131044119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97992800 + ... + 97992933.

It is an arithmetic number, because the mean of its divisors is an integer number (3331757478).

Almost surely, 2^13131044111 is an apocalyptic number.

13131044111 is a deficient number, since it is larger than the sum of its proper divisors (195985801).

13131044111 is an equidigital number, since it uses as much as digits as its factorization.

13131044111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 195985800.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13131044111 its reverse (11144013131), we get a palindrome (24275057242).

The spelling of 13131044111 in words is "thirteen billion, one hundred thirty-one million, forty-four thousand, one hundred eleven".