11144013131 has 4 divisors (see below), whose sum is σ = 11144242032. Its totient is φ = 11143784232.

The previous prime is 11144013109. The next prime is 11144013137. The reversal of 11144013131 is 13131044111.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13131044111 = 67 ⋅195985733.

It is a cyclic number.

It is not a de Polignac number, because 11144013131 - 2¹⁸ = 11143750987 is a prime.

It is a super-2 number, since 2×11144013131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11144013137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9095 + ... + 149568.

It is an arithmetic number, because the mean of its divisors is an integer number (2786060508).

Almost surely, 2^11144013131 is an apocalyptic number.

11144013131 is a deficient number, since it is larger than the sum of its proper divisors (228901).

11144013131 is an equidigital number, since it uses as much as digits as its factorization.

11144013131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 228900.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 11144013131 its reverse (13131044111), we get a palindrome (24275057242).

The spelling of 11144013131 in words is "eleven billion, one hundred forty-four million, thirteen thousand, one hundred thirty-one".