13131104042351 has 4 divisors (see below), whose sum is σ = 13197089490000. Its totient is φ = 13065118594704.

The previous prime is 13131104042291. The next prime is 13131104042363. The reversal of 13131104042351 is 15324040113131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13131104042351 - 2²² = 13131099848047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131104042951) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32992723526 + ... + 32992723923.

It is an arithmetic number, because the mean of its divisors is an integer number (3299272372500).

Almost surely, 2^{13131104042351} is an apocalyptic number.

13131104042351 is a deficient number, since it is larger than the sum of its proper divisors (65985447649).

13131104042351 is an equidigital number, since it uses as much as digits as its factorization.

13131104042351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65985447648.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 13131104042351 its reverse (15324040113131), we get a palindrome (28455144155482).

The spelling of 13131104042351 in words is "thirteen trillion, one hundred thirty-one billion, one hundred four million, forty-two thousand, three hundred fifty-one".