Base | Representation |
---|---|
bin | 11101110110110100111111… |
… | …100011000111111111101010 |
3 | 122012221012220102102212112210 |
4 | 131312310333203013333222 |
5 | 114202400113414004002 |
6 | 1143135253121145550 |
7 | 36441625334040162 |
oct | 3566647743077752 |
9 | 565835812385483 |
10 | 131311101313002 |
11 | 389267a8466166 |
12 | 12888b7a18b2b6 |
13 | 583677858a290 |
14 | 245d6c3c6b5a2 |
15 | 102aa82dc196c |
hex | 776d3f8c7fea |
131311101313002 has 32 divisors (see below), whose sum is σ = 289722054686400. Its totient is φ = 39417966622080.
The previous prime is 131311101312967. The next prime is 131311101313003. The reversal of 131311101313002 is 200313101113131.
It is a self number, because there is not a number n which added to its sum of digits gives 131311101313002.
It is not an unprimeable number, because it can be changed into a prime (131311101313003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20530187752 + ... + 20530194147.
It is an arithmetic number, because the mean of its divisors is an integer number (9053814208950).
Almost surely, 2131311101313002 is an apocalyptic number.
131311101313002 is an abundant number, since it is smaller than the sum of its proper divisors (158410953373398).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131311101313002 is a wasteful number, since it uses less digits than its factorization.
131311101313002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41060381958.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 131311101313002 its reverse (200313101113131), we get a palindrome (331624202426133).
The spelling of 131311101313002 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred one million, three hundred thirteen thousand, two".
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