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131311103321353 is a prime number
BaseRepresentation
bin11101110110110100111111…
…101010110010010100001001
3122012221012220120012220111011
4131312310333222302110021
5114202400114422240403
61143135253232203521
736441625360103344
oct3566647752622411
9565835816186434
10131311103321353
11389267a960805a
1212888b7a9995a1
135836778b11457
14245d6c423145b
15102aa8316ba6d
hex776d3fab2509

131311103321353 has 2 divisors, whose sum is σ = 131311103321354. Its totient is φ = 131311103321352.

The previous prime is 131311103321309. The next prime is 131311103321407. The reversal of 131311103321353 is 353123301113131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126173392032249 + 5137711289104 = 11232693^2 + 2266652^2 .

It is an emirp because it is prime and its reverse (353123301113131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131311103321353 is a prime.

It is not a weakly prime, because it can be changed into another prime (131311103321953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655551660676 + 65655551660677.

It is an arithmetic number, because the mean of its divisors is an integer number (65655551660677).

Almost surely, 2131311103321353 is an apocalyptic number.

It is an amenable number.

131311103321353 is a deficient number, since it is larger than the sum of its proper divisors (1).

131311103321353 is an equidigital number, since it uses as much as digits as its factorization.

131311103321353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7290, while the sum is 31.

Adding to 131311103321353 its reverse (353123301113131), we get a palindrome (484434404434484).

The spelling of 131311103321353 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred three million, three hundred twenty-one thousand, three hundred fifty-three".