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1313111123102 = 2656555561551
BaseRepresentation
bin10011000110111011100…
…001011010010010011110
311122112100222020111221002
4103012323201122102132
5133003222421414402
62443122424310302
7163604055246152
oct23067341322236
94575328214832
101313111123102
11466983aa6019
121925a6312392
1396a9750574c
14477aa99d062
1524254ec7602
hex131bb85a49e

1313111123102 has 4 divisors (see below), whose sum is σ = 1969666684656. Its totient is φ = 656555561550.

The previous prime is 1313111123101. The next prime is 1313111123111. The reversal of 1313111123102 is 2013211113131.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×13131111231022 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313111123101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328277780774 + ... + 328277780777.

It is an arithmetic number, because the mean of its divisors is an integer number (492416671164).

Almost surely, 21313111123102 is an apocalyptic number.

1313111123102 is a deficient number, since it is larger than the sum of its proper divisors (656555561554).

1313111123102 is an equidigital number, since it uses as much as digits as its factorization.

1313111123102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656555561553.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1313111123102 its reverse (2013211113131), we get a palindrome (3326322236233).

The spelling of 1313111123102 in words is "one trillion, three hundred thirteen billion, one hundred eleven million, one hundred twenty-three thousand, one hundred two".

Divisors: 1 2 656555561551 1313111123102