Search a number
-
+
13131112044 = 2231094259337
BaseRepresentation
bin11000011101010110…
…01101111001101100
31020220010111121101010
430032223031321230
5203343031041134
610010553145220
7643254416331
oct141653157154
936803447333
1013131112044
115629196916
1226656bb210
1313135b96ab
148c7d38988
1551cbeece9
hex30eacde6c

13131112044 has 12 divisors (see below), whose sum is σ = 30639261464. Its totient is φ = 4377037344.

The previous prime is 13131111977. The next prime is 13131112079. The reversal of 13131112044 is 44021113131.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×131311120442 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13131112044.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547129657 + ... + 547129680.

Almost surely, 213131112044 is an apocalyptic number.

It is an amenable number.

13131112044 is an abundant number, since it is smaller than the sum of its proper divisors (17508149420).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13131112044 is a wasteful number, since it uses less digits than its factorization.

13131112044 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1094259344 (or 1094259342 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 13131112044 its reverse (44021113131), we get a palindrome (57152225175).

The spelling of 13131112044 in words is "thirteen billion, one hundred thirty-one million, one hundred twelve thousand, forty-four".

Divisors: 1 2 3 4 6 12 1094259337 2188518674 3282778011 4377037348 6565556022 13131112044