Base | Representation |
---|---|
bin | 11101110110110101000001… |
… | …010001110000000100101011 |
3 | 122012221012222110000020001220 |
4 | 131312311001101300010223 |
5 | 114202400143330004003 |
6 | 1143135300034513123 |
7 | 36441626135402244 |
oct | 3566650121600453 |
9 | 565835873006056 |
10 | 131311130313003 |
11 | 38926812873303 |
12 | 12888b87a357a3 |
13 | 58367815a2044 |
14 | 245d6c7a59ccb |
15 | 102aa856ee353 |
hex | 776d4147012b |
131311130313003 has 48 divisors (see below), whose sum is σ = 200553806113920. Its totient is φ = 75945320354304.
The previous prime is 131311130312959. The next prime is 131311130313031. The reversal of 131311130313003 is 300313031113131.
It is not a de Polignac number, because 131311130313003 - 29 = 131311130312491 is a prime.
It is a super-2 number, since 2×1313111303130032 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131311130313073) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 48166501 + ... + 50819622.
It is an arithmetic number, because the mean of its divisors is an integer number (4178204294040).
Almost surely, 2131311130313003 is an apocalyptic number.
131311130313003 is a deficient number, since it is larger than the sum of its proper divisors (69242675800917).
131311130313003 is a wasteful number, since it uses less digits than its factorization.
131311130313003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98986236 (or 98986199 counting only the distinct ones).
The product of its (nonzero) digits is 729, while the sum is 24.
Adding to 131311130313003 its reverse (300313031113131), we get a palindrome (431624161426134).
The spelling of 131311130313003 in words is "one hundred thirty-one trillion, three hundred eleven billion, one hundred thirty million, three hundred thirteen thousand, three".
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