131311312333 has 4 divisors (see below), whose sum is σ = 131313819040. Its totient is φ = 131308805628.

The previous prime is 131311312309. The next prime is 131311312453. The reversal of 131311312333 is 333213113131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131311312333 is a prime.

It is a super-2 number, since 2×131311312333² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131311312298 and 131311312307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131311312633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1173063 + ... + 1280116.

It is an arithmetic number, because the mean of its divisors is an integer number (32828454760).

Almost surely, 2^131311312333 is an apocalyptic number.

It is an amenable number.

131311312333 is a deficient number, since it is larger than the sum of its proper divisors (2506707).

131311312333 is an equidigital number, since it uses as much as digits as its factorization.

131311312333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2506706.

The product of its digits is 1458, while the sum is 25.

Adding to 131311312333 its reverse (333213113131), we get a palindrome (464524425464).

The spelling of 131311312333 in words is "one hundred thirty-one billion, three hundred eleven million, three hundred twelve thousand, three hundred thirty-three".