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131311400202022 = 2376431744167577
BaseRepresentation
bin11101110110110101010001…
…010111010010111100100110
3122012221020200020212000012111
4131312311101113102330212
5114202401221422431042
61143135342515311234
736441635623411555
oct3566652127227446
9565836606760174
10131311400202022
1138926941150987
12128890422ab51a
1358367c54894a1
14245d711831d9c
15102aa9e261517
hex776d515d2f26

131311400202022 has 8 divisors (see below), whose sum is σ = 196972332918696. Its totient is φ = 65653955895792.

The previous prime is 131311400201941. The next prime is 131311400202061. The reversal of 131311400202022 is 220202004113131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 131311400201984 and 131311400202002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 872008503 + ... + 872159074.

It is an arithmetic number, because the mean of its divisors is an integer number (24621541614837).

Almost surely, 2131311400202022 is an apocalyptic number.

131311400202022 is a deficient number, since it is larger than the sum of its proper divisors (65660932716674).

131311400202022 is a wasteful number, since it uses less digits than its factorization.

131311400202022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1744205222.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 131311400202022 its reverse (220202004113131), we get a palindrome (351513404315153).

The spelling of 131311400202022 in words is "one hundred thirty-one trillion, three hundred eleven billion, four hundred million, two hundred two thousand, twenty-two".

Divisors: 1 2 37643 75286 1744167577 3488335154 65655700101011 131311400202022