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13131201330281 is a prime number
BaseRepresentation
bin1011111100010101100010…
…0101110011110001101001
31201111022220222221200020102
42333011120211303301221
53210120200020032111
643532220212235145
72523461260454366
oct277053045636151
951438828850212
1013131201330281
114202a02904071
121580ab890bab5
137433616cba68
143357a6c8946d
1517b88cbea13b
hexbf158973c69

13131201330281 has 2 divisors, whose sum is σ = 13131201330282. Its totient is φ = 13131201330280.

The previous prime is 13131201330277. The next prime is 13131201330337. The reversal of 13131201330281 is 18203310213131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12383220240400 + 747981089881 = 3518980^2 + 864859^2 .

It is a cyclic number.

It is not a de Polignac number, because 13131201330281 - 22 = 13131201330277 is a prime.

It is a super-2 number, since 2×131312013302812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13131201830281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565600665140 + 6565600665141.

It is an arithmetic number, because the mean of its divisors is an integer number (6565600665141).

Almost surely, 213131201330281 is an apocalyptic number.

It is an amenable number.

13131201330281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131201330281 is an equidigital number, since it uses as much as digits as its factorization.

13131201330281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 13131201330281 in words is "thirteen trillion, one hundred thirty-one billion, two hundred one million, three hundred thirty thousand, two hundred eighty-one".