Base | Representation |
---|---|
bin | 1011111100010101100010… |
… | …0110000111100101010001 |
3 | 1201111022221000002210112011 |
4 | 2333011120212013211101 |
5 | 3210120200030131114 |
6 | 43532220214102521 |
7 | 2523461261243044 |
oct | 277053046074521 |
9 | 51438830083464 |
10 | 13131201411409 |
11 | 4202a0295a014 |
12 | 1580ab894aa41 |
13 | 743361729973 |
14 | 3357a6caac5b |
15 | 17b88cc141c4 |
hex | bf158987951 |
13131201411409 has 2 divisors, whose sum is σ = 13131201411410. Its totient is φ = 13131201411408.
The previous prime is 13131201411379. The next prime is 13131201411457. The reversal of 13131201411409 is 90411410213131.
13131201411409 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12659648641600 + 471552769809 = 3558040^2 + 686697^2 .
It is a cyclic number.
It is not a de Polignac number, because 13131201411409 - 225 = 13131167856977 is a prime.
It is not a weakly prime, because it can be changed into another prime (13131201411469) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565600705704 + 6565600705705.
It is an arithmetic number, because the mean of its divisors is an integer number (6565600705705).
Almost surely, 213131201411409 is an apocalyptic number.
It is an amenable number.
13131201411409 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131201411409 is an equidigital number, since it uses as much as digits as its factorization.
13131201411409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 31.
The spelling of 13131201411409 in words is "thirteen trillion, one hundred thirty-one billion, two hundred one million, four hundred eleven thousand, four hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •