Search a number
-
+
13131204031342 = 26565602015671
BaseRepresentation
bin1011111100010101100011…
…0000000111001101101110
31201111022221012000220101201
42333011120300013031232
53210120201213000332
643532220350200114
72523461322434245
oct277053060071556
951438835026351
1013131204031342
114202a04389451
121580ab97b303a
13743362136317
143357a738d95c
1517b88d0805e7
hexbf158c0736e

13131204031342 has 4 divisors (see below), whose sum is σ = 19696806047016. Its totient is φ = 6565602015670.

The previous prime is 13131204031339. The next prime is 13131204031391. The reversal of 13131204031342 is 24313040213131.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13131204031342.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282801007834 + ... + 3282801007837.

It is an arithmetic number, because the mean of its divisors is an integer number (4924201511754).

Almost surely, 213131204031342 is an apocalyptic number.

13131204031342 is a deficient number, since it is larger than the sum of its proper divisors (6565602015674).

13131204031342 is an equidigital number, since it uses as much as digits as its factorization.

13131204031342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6565602015673.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 13131204031342 its reverse (24313040213131), we get a palindrome (37444244244473).

The spelling of 13131204031342 in words is "thirteen trillion, one hundred thirty-one billion, two hundred four million, thirty-one thousand, three hundred forty-two".

Divisors: 1 2 6565602015671 13131204031342