1313121251041 has 4 divisors (see below), whose sum is σ = 1317966717184. Its totient is φ = 1308275784900.

The previous prime is 1313121251011. The next prime is 1313121251047. The reversal of 1313121251041 is 1401521213131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313121251041 - 2²¹ = 1313119153889 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1313121250997 and 1313121251015.

It is not an unprimeable number, because it can be changed into a prime (1313121251047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2422732665 + ... + 2422733206.

It is an arithmetic number, because the mean of its divisors is an integer number (329491679296).

Almost surely, 2^{1313121251041} is an apocalyptic number.

It is an amenable number.

1313121251041 is a deficient number, since it is larger than the sum of its proper divisors (4845466143).

1313121251041 is an equidigital number, since it uses as much as digits as its factorization.

1313121251041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4845466142.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 1313121251041 its reverse (1401521213131), we get a palindrome (2714642464172).

The spelling of 1313121251041 in words is "one trillion, three hundred thirteen billion, one hundred twenty-one million, two hundred fifty-one thousand, forty-one".