1401521213131 has 8 divisors (see below), whose sum is σ = 1510222073360. Its totient is φ = 1292947715232.

The previous prime is 1401521213119. The next prime is 1401521213153. The reversal of 1401521213131 is 1313121251041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1401521213131 - 2¹³ = 1401521204939 is a prime.

It is a super-2 number, since 2×1401521213131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1401521213096 and 1401521213105.

It is not an unprimeable number, because it can be changed into a prime (1401521213171) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31817721 + ... + 31861738.

It is an arithmetic number, because the mean of its divisors is an integer number (188777759170).

Almost surely, 2^{1401521213131} is an apocalyptic number.

1401521213131 is a deficient number, since it is larger than the sum of its proper divisors (108700860229).

1401521213131 is a wasteful number, since it uses less digits than its factorization.

1401521213131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63681165.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 1401521213131 its reverse (1313121251041), we get a palindrome (2714642464172).

The spelling of 1401521213131 in words is "one trillion, four hundred one billion, five hundred twenty-one million, two hundred thirteen thousand, one hundred thirty-one".