Base | Representation |
---|---|
bin | 10011000110111100101… |
… | …001011011100001100011 |
3 | 11122112102021202200122012 |
4 | 103012330221123201203 |
5 | 133003242240040111 |
6 | 2443124341103135 |
7 | 163604404600214 |
oct | 23067451334143 |
9 | 4575367680565 |
10 | 1313130002531 |
11 | 466993720456 |
12 | 1925b06b7aab |
13 | 96a9b3b5ac9 |
14 | 477ad2b540b |
15 | 242569a648b |
hex | 131bca5b863 |
1313130002531 has 2 divisors, whose sum is σ = 1313130002532. Its totient is φ = 1313130002530.
The previous prime is 1313130002507. The next prime is 1313130002623. The reversal of 1313130002531 is 1352000313131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313130002531 - 222 = 1313125808227 is a prime.
It is a super-2 number, since 2×13131300025312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1313130002497 and 1313130002506.
It is not a weakly prime, because it can be changed into another prime (1313130002731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656565001265 + 656565001266.
It is an arithmetic number, because the mean of its divisors is an integer number (656565001266).
Almost surely, 21313130002531 is an apocalyptic number.
1313130002531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313130002531 is an equidigital number, since it uses as much as digits as its factorization.
1313130002531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 1313130002531 its reverse (1352000313131), we get a palindrome (2665130315662).
The spelling of 1313130002531 in words is "one trillion, three hundred thirteen billion, one hundred thirty million, two thousand, five hundred thirty-one".
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