1313130113 has 2 divisors, whose sum is σ = 1313130114. Its totient is φ = 1313130112.

The previous prime is 1313130101. The next prime is 1313130139. The reversal of 1313130113 is 3110313131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 862714384 + 450415729 = 29372^2 + 21223^2 .

It is an emirp because it is prime and its reverse (3110313131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313130113 - 2⁴ = 1313130097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1313130091 and 1313130100.

It is not a weakly prime, because it can be changed into another prime (1313130913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656565056 + 656565057.

It is an arithmetic number, because the mean of its divisors is an integer number (656565057).

Almost surely, 2^1313130113 is an apocalyptic number.

It is an amenable number.

1313130113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313130113 is an equidigital number, since it uses as much as digits as its factorization.

1313130113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

The square root of 1313130113 is about 36237.1372075665. The cubic root of 1313130113 is about 1095.0549691274.

Adding to 1313130113 its reverse (3110313131), we get a palindrome (4423443244).

The spelling of 1313130113 in words is "one billion, three hundred thirteen million, one hundred thirty thousand, one hundred thirteen".