Base | Representation |
---|---|
bin | 111101001001011011… |
… | …1011101001101110001 |
3 | 110112221102122002011121 |
4 | 1322102313131031301 |
5 | 4122412113430001 |
6 | 140154021542241 |
7 | 12326026224106 |
oct | 1722267351561 |
9 | 415842562147 |
10 | 131313030001 |
11 | 50764866a9a |
12 | 21548574981 |
13 | c4c8c2256a |
14 | 64d9a1caad |
15 | 36382796a1 |
hex | 1e92ddd371 |
131313030001 has 2 divisors, whose sum is σ = 131313030002. Its totient is φ = 131313030000.
The previous prime is 131313029941. The next prime is 131313030067. The reversal of 131313030001 is 100030313131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118594829376 + 12718200625 = 344376^2 + 112775^2 .
It is a cyclic number.
It is not a de Polignac number, because 131313030001 - 213 = 131313021809 is a prime.
It is a super-2 number, since 2×1313130300012 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131313030601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656515000 + 65656515001.
It is an arithmetic number, because the mean of its divisors is an integer number (65656515001).
Almost surely, 2131313030001 is an apocalyptic number.
It is an amenable number.
131313030001 is a deficient number, since it is larger than the sum of its proper divisors (1).
131313030001 is an equidigital number, since it uses as much as digits as its factorization.
131313030001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 131313030001 its reverse (100030313131), we get a palindrome (231343343132).
The spelling of 131313030001 in words is "one hundred thirty-one billion, three hundred thirteen million, thirty thousand, one".
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