1313131020001 has 2 divisors, whose sum is σ = 1313131020002. Its totient is φ = 1313131020000.

The previous prime is 1313131019969. The next prime is 1313131020023. The reversal of 1313131020001 is 1000201313131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1092963611601 + 220167408400 = 1045449^2 + 469220^2 .

It is an emirp because it is prime and its reverse (1000201313131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313131020001 - 2⁵ = 1313131019969 is a prime.

It is not a weakly prime, because it can be changed into another prime (1313131020101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656565510000 + 656565510001.

It is an arithmetic number, because the mean of its divisors is an integer number (656565510001).

Almost surely, 2^{1313131020001} is an apocalyptic number.

It is an amenable number.

1313131020001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313131020001 is an equidigital number, since it uses as much as digits as its factorization.

1313131020001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1313131020001 its reverse (1000201313131), we get a palindrome (2313332333132).

The spelling of 1313131020001 in words is "one trillion, three hundred thirteen billion, one hundred thirty-one million, twenty thousand, one".