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131313232133113 is a prime number
BaseRepresentation
bin11101110110110110111110…
…100011100011101111111001
3122012221102101220221202020011
4131312312332203203233321
5114202413444411224423
61143140244400101521
736442032206516542
oct3566667643435771
9565842356852204
10131313232133113
11389276a1234918
12128894739048a1
135836a27b79494
14245d846c5b4c9
15102ab59ec5b0d
hex776dbe8e3bf9

131313232133113 has 2 divisors, whose sum is σ = 131313232133114. Its totient is φ = 131313232133112.

The previous prime is 131313232133077. The next prime is 131313232133141. The reversal of 131313232133113 is 311331232313131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118273716138384 + 13039515994729 = 10875372^2 + 3611027^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131313232133113 is a prime.

It is not a weakly prime, because it can be changed into another prime (131313232133513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65656616066556 + 65656616066557.

It is an arithmetic number, because the mean of its divisors is an integer number (65656616066557).

Almost surely, 2131313232133113 is an apocalyptic number.

It is an amenable number.

131313232133113 is a deficient number, since it is larger than the sum of its proper divisors (1).

131313232133113 is an equidigital number, since it uses as much as digits as its factorization.

131313232133113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 8748, while the sum is 31.

Adding to 131313232133113 its reverse (311331232313131), we get a palindrome (442644464446244).

The spelling of 131313232133113 in words is "one hundred thirty-one trillion, three hundred thirteen billion, two hundred thirty-two million, one hundred thirty-three thousand, one hundred thirteen".