Base | Representation |
---|---|
bin | 11101110110110111000011… |
… | …010001000000001101011011 |
3 | 122012221102121102122110221000 |
4 | 131312313003101000031123 |
5 | 114202414130123430120 |
6 | 1143140300301520043 |
7 | 36442034156300262 |
oct | 3566670321001533 |
9 | 565842542573830 |
10 | 131313311155035 |
11 | 389277318a8199 |
12 | 12889496273023 |
13 | 5836a3b356609 |
14 | 245d85354b5d9 |
15 | 102ab61dd4990 |
hex | 776dc344035b |
131313311155035 has 64 divisors (see below), whose sum is σ = 244871078952960. Its totient is φ = 66638092498560.
The previous prime is 131313311154983. The next prime is 131313311155067. The reversal of 131313311155035 is 530551113313131.
131313311155035 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 1 + 3 + 31 + 115 + 503 + 5 = 666.
It is not a de Polignac number, because 131313311155035 - 211 = 131313311152987 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 110116164 + ... + 111302273.
It is an arithmetic number, because the mean of its divisors is an integer number (3826110608640).
Almost surely, 2131313311155035 is an apocalyptic number.
131313311155035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131313311155035 is a deficient number, since it is larger than the sum of its proper divisors (113557767797925).
131313311155035 is a wasteful number, since it uses less digits than its factorization.
131313311155035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 221418665 (or 221418659 counting only the distinct ones).
The product of its (nonzero) digits is 30375, while the sum is 36.
Adding to 131313311155035 its reverse (530551113313131), we get a palindrome (661864424468166).
The spelling of 131313311155035 in words is "one hundred thirty-one trillion, three hundred thirteen billion, three hundred eleven million, one hundred fifty-five thousand, thirty-five".
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