Base | Representation |
---|---|
bin | 11101110110110111000100… |
… | …011001000011110110110101 |
3 | 122012221102122202012011011221 |
4 | 131312313010121003312311 |
5 | 114202414144442404331 |
6 | 1143140302214430341 |
7 | 36442034505662164 |
oct | 3566670431036665 |
9 | 565842582164157 |
10 | 131313330044341 |
11 | 38927741529a95 |
12 | 128894a06623b1 |
13 | 5836a4223b313 |
14 | 245d855c673db |
15 | 102ab638b6711 |
hex | 776dc4643db5 |
131313330044341 has 4 divisors (see below), whose sum is σ = 133273230492832. Its totient is φ = 129353429595852.
The previous prime is 131313330044339. The next prime is 131313330044353. The reversal of 131313330044341 is 143440033313131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131313330044341 - 21 = 131313330044339 is a prime.
It is a super-2 number, since 2×1313133300443412 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131313330044297 and 131313330044306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131313330044041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 979950224145 + ... + 979950224278.
It is an arithmetic number, because the mean of its divisors is an integer number (33318307623208).
Almost surely, 2131313330044341 is an apocalyptic number.
It is an amenable number.
131313330044341 is a deficient number, since it is larger than the sum of its proper divisors (1959900448491).
131313330044341 is an equidigital number, since it uses as much as digits as its factorization.
131313330044341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1959900448490.
The product of its (nonzero) digits is 46656, while the sum is 34.
Adding to 131313330044341 its reverse (143440033313131), we get a palindrome (274753363357472).
The spelling of 131313330044341 in words is "one hundred thirty-one trillion, three hundred thirteen billion, three hundred thirty million, forty-four thousand, three hundred forty-one".
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