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13131400124551 = 73179882193487
BaseRepresentation
bin1011111100010110010001…
…1100001001100010000111
31201111100102212000110201011
42333011210130021202013
53210121101412441201
643532252033143051
72523466223260462
oct277054434114207
951440385013634
1013131400124551
114202aa5043155
121580b533baa87
137433939532c7
143357c54362d9
1517b8a03b7151
hexbf164709887

13131400124551 has 4 divisors (see below), whose sum is σ = 13311282318112. Its totient is φ = 12951517930992.

The previous prime is 13131400124533. The next prime is 13131400124567. The reversal of 13131400124551 is 15542100413131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13131400124551 - 217 = 13131399993479 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131400124581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89941096671 + ... + 89941096816.

It is an arithmetic number, because the mean of its divisors is an integer number (3327820579528).

Almost surely, 213131400124551 is an apocalyptic number.

13131400124551 is a deficient number, since it is larger than the sum of its proper divisors (179882193561).

13131400124551 is an equidigital number, since it uses as much as digits as its factorization.

13131400124551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 179882193560.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 13131400124551 its reverse (15542100413131), we get a palindrome (28673500537682).

The spelling of 13131400124551 in words is "thirteen trillion, one hundred thirty-one billion, four hundred million, one hundred twenty-four thousand, five hundred fifty-one".

Divisors: 1 73 179882193487 13131400124551