Base | Representation |
---|---|
bin | 11101110110110111111001… |
… | …101100110101110011101011 |
3 | 122012221111222002010020211222 |
4 | 131312313321230311303223 |
5 | 114202423012423001443 |
6 | 1143140531044212255 |
7 | 36442065616033451 |
oct | 3566677154656353 |
9 | 565844862106758 |
10 | 131314224422123 |
11 | 38928060371286 |
12 | 128896b009a08b |
13 | 5836b55616942 |
14 | 245d8dc95c9d1 |
15 | 102abb7182468 |
hex | 776df9b35ceb |
131314224422123 has 2 divisors, whose sum is σ = 131314224422124. Its totient is φ = 131314224422122.
The previous prime is 131314224422113. The next prime is 131314224422137. The reversal of 131314224422123 is 321224422413131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131314224422123 - 232 = 131309929454827 is a prime.
It is a super-3 number, since 3×1313142244221233 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (131314224422113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65657112211061 + 65657112211062.
It is an arithmetic number, because the mean of its divisors is an integer number (65657112211062).
Almost surely, 2131314224422123 is an apocalyptic number.
131314224422123 is a deficient number, since it is larger than the sum of its proper divisors (1).
131314224422123 is an equidigital number, since it uses as much as digits as its factorization.
131314224422123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 55296, while the sum is 35.
Adding to 131314224422123 its reverse (321224422413131), we get a palindrome (452538646835254).
The spelling of 131314224422123 in words is "one hundred thirty-one trillion, three hundred fourteen billion, two hundred twenty-four million, four hundred twenty-two thousand, one hundred twenty-three".
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