131314301 has 4 divisors (see below), whose sum is σ = 138225600. Its totient is φ = 124403004.

The previous prime is 131314289. The next prime is 131314319. The reversal of 131314301 is 103413131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 103413131 = 373 ⋅277247.

It is a cyclic number.

It is not a de Polignac number, because 131314301 - 2¹⁴ = 131297917 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 131314301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131314321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3455621 + ... + 3455658.

It is an arithmetic number, because the mean of its divisors is an integer number (34556400).

Almost surely, 2^131314301 is an apocalyptic number.

It is an amenable number.

131314301 is a deficient number, since it is larger than the sum of its proper divisors (6911299).

131314301 is an equidigital number, since it uses as much as digits as its factorization.

131314301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6911298.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 131314301 is about 11459.2452194724. The cubic root of 131314301 is about 508.2811557182.

Adding to 131314301 its reverse (103413131), we get a palindrome (234727432).

It can be divided in two parts, 131 and 314301, that added together give a cube (314432 = 68³).

The spelling of 131314301 in words is "one hundred thirty-one million, three hundred fourteen thousand, three hundred one".