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13131522019999 = 41549316049051
BaseRepresentation
bin1011111100010110101110…
…1101001001001010011111
31201111100202100101101211101
42333011223231021022133
53210121324114114444
643532312105533531
72523502233335005
oct277055355111237
951440670341741
1013131522019999
114203057929a99
121580b881a42a7
137433b2c91ba6
143357d76c6a75
1517b8aae443d4
hexbf16bb4929f

13131522019999 has 4 divisors (see below), whose sum is σ = 13131838110600. Its totient is φ = 13131205929400.

The previous prime is 13131522019991. The next prime is 13131522020003. The reversal of 13131522019999 is 99991022513131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13131522019999 - 23 = 13131522019991 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13131522019991) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157982977 + ... + 158066074.

It is an arithmetic number, because the mean of its divisors is an integer number (3282959527650).

Almost surely, 213131522019999 is an apocalyptic number.

13131522019999 is a deficient number, since it is larger than the sum of its proper divisors (316090601).

13131522019999 is an equidigital number, since it uses as much as digits as its factorization.

13131522019999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 316090600.

The product of its (nonzero) digits is 1180980, while the sum is 55.

The spelling of 13131522019999 in words is "thirteen trillion, one hundred thirty-one billion, five hundred twenty-two million, nineteen thousand, nine hundred ninety-nine".

Divisors: 1 41549 316049051 13131522019999