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1313170153 = 7916622407
BaseRepresentation
bin100111001000101…
…0110001011101001
310101111221221210121
41032101112023221
510142132421103
6334145443241
744353522261
oct11621261351
93344857717
101313170153
11614283199
12307940521
1317c099779
14c658c7a1
157a4426bd
hex4e4562e9

1313170153 has 4 divisors (see below), whose sum is σ = 1329792640. Its totient is φ = 1296547668.

The previous prime is 1313170147. The next prime is 1313170213. The reversal of 1313170153 is 3510713131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313170153 - 213 = 1313161961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1313173153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8311125 + ... + 8311282.

It is an arithmetic number, because the mean of its divisors is an integer number (332448160).

Almost surely, 21313170153 is an apocalyptic number.

It is an amenable number.

1313170153 is a deficient number, since it is larger than the sum of its proper divisors (16622487).

1313170153 is an equidigital number, since it uses as much as digits as its factorization.

1313170153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16622486.

The product of its (nonzero) digits is 945, while the sum is 25.

The square root of 1313170153 is about 36237.6896752539. The cubic root of 1313170153 is about 1095.0660991631.

Adding to 1313170153 its reverse (3510713131), we get a palindrome (4823883284).

The spelling of 1313170153 in words is "one billion, three hundred thirteen million, one hundred seventy thousand, one hundred fifty-three".

Divisors: 1 79 16622407 1313170153