Base | Representation |
---|---|
bin | 10011000111000000100… |
… | …111000100111101110011 |
3 | 11122112120220212211202101 |
4 | 103013000213010331303 |
5 | 133003411300312312 |
6 | 2443135114201231 |
7 | 163606143014026 |
oct | 23070047047563 |
9 | 4575526784671 |
10 | 1313196494707 |
11 | 466a18205a69 |
12 | 19260aa23217 |
13 | 96aac0c6aa6 |
14 | 477b80631bd |
15 | 2425c73ca57 |
hex | 131c09c4f73 |
1313196494707 has 2 divisors, whose sum is σ = 1313196494708. Its totient is φ = 1313196494706.
The previous prime is 1313196494699. The next prime is 1313196494711. The reversal of 1313196494707 is 7074946913131.
It is a strong prime.
It is an emirp because it is prime and its reverse (7074946913131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313196494707 - 23 = 1313196494699 is a prime.
It is not a weakly prime, because it can be changed into another prime (1313196498707) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656598247353 + 656598247354.
It is an arithmetic number, because the mean of its divisors is an integer number (656598247354).
Almost surely, 21313196494707 is an apocalyptic number.
1313196494707 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313196494707 is an equidigital number, since it uses as much as digits as its factorization.
1313196494707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3429216, while the sum is 55.
The spelling of 1313196494707 in words is "one trillion, three hundred thirteen billion, one hundred ninety-six million, four hundred ninety-four thousand, seven hundred seven".
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