Base | Representation |
---|---|
bin | 11101110110111101010010… |
… | …101110111111001011001100 |
3 | 122012222001220111120210101220 |
4 | 131312331102232333023030 |
5 | 114203021341324434200 |
6 | 1143143325312203340 |
7 | 36442362226141260 |
oct | 3566752256771314 |
9 | 565861814523356 |
10 | 131320013124300 |
11 | 3892a5609a2970 |
12 | 1288a846839550 |
13 | 58375689a0bc0 |
14 | 245dccb6880a0 |
15 | 102ae0547d4a0 |
hex | 776f52bbf2cc |
131320013124300 has 576 divisors, whose sum is σ = 523933886751744. Its totient is φ = 24507488563200.
The previous prime is 131320013124259. The next prime is 131320013124323. The reversal of 131320013124300 is 3421310023131.
It is an unprimeable number.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 5201694 + ... + 17020506.
Almost surely, 2131320013124300 is an apocalyptic number.
131320013124300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131320013124300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (261966943375872).
131320013124300 is an abundant number, since it is smaller than the sum of its proper divisors (392613873627444).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131320013124300 is a wasteful number, since it uses less digits than its factorization.
131320013124300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11818898 (or 11818891 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 131320013124300 its reverse (3421310023131), we get a palindrome (134741323147431).
The spelling of 131320013124300 in words is "one hundred thirty-one trillion, three hundred twenty billion, thirteen million, one hundred twenty-four thousand, three hundred".
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