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1313200445000 = 235417471911721
BaseRepresentation
bin10011000111000000110…
…110001001011001001000
311122112121012022112112112
4103013000312021121020
5133003413303220000
62443135335001452
7163606221415643
oct23070066113110
94575535275475
101313200445000
11466a1a463974
12192610209288
1396aacb7ab42
14477b87b0a5a
152425cc6d235
hex131c0d89648

1313200445000 has 320 divisors, whose sum is σ = 3346496778240. Its totient is φ = 481049600000.

The previous prime is 1313200444993. The next prime is 1313200445021. The reversal of 1313200445000 is 5440023131.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 763044140 + ... + 763045860.

It is an arithmetic number, because the mean of its divisors is an integer number (10457802432).

Almost surely, 21313200445000 is an apocalyptic number.

1313200445000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1313200445000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1673248389120).

1313200445000 is an abundant number, since it is smaller than the sum of its proper divisors (2033296333240).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1313200445000 is a wasteful number, since it uses less digits than its factorization.

1313200445000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2002 (or 1983 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 1313200445000 its reverse (5440023131), we get a palindrome (1318640468131).

The spelling of 1313200445000 in words is "one trillion, three hundred thirteen billion, two hundred million, four hundred forty-five thousand".