13132024331434 has 4 divisors (see below), whose sum is σ = 19698036497154. Its totient is φ = 6566012165716.

The previous prime is 13132024331429. The next prime is 13132024331443. The reversal of 13132024331434 is 43413342023131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11480678539225 + 1651345792209 = 3388315^2 + 1285047^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13132024331434.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283006082857 + ... + 3283006082860.

Almost surely, 2^{13132024331434} is an apocalyptic number.

13132024331434 is a deficient number, since it is larger than the sum of its proper divisors (6566012165720).

13132024331434 is an equidigital number, since it uses as much as digits as its factorization.

13132024331434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6566012165719.

The product of its (nonzero) digits is 62208, while the sum is 34.

Adding to 13132024331434 its reverse (43413342023131), we get a palindrome (56545366354565).

The spelling of 13132024331434 in words is "thirteen trillion, one hundred thirty-two billion, twenty-four million, three hundred thirty-one thousand, four hundred thirty-four".