Base | Representation |
---|---|
bin | 1011111100011000101000… |
… | …0111010101010100100011 |
3 | 1201111102001220101022222202 |
4 | 2333012022013111110203 |
5 | 3210123400220431034 |
6 | 43532434452523415 |
7 | 2523520666660103 |
oct | 277061207252443 |
9 | 51442056338882 |
10 | 13132032202019 |
11 | 4203299910325 |
12 | 15810ab02056b |
13 | 7434648a0643 |
14 | 33584536d203 |
15 | 17b8dab1e47e |
hex | bf18a1d5523 |
13132032202019 has 2 divisors, whose sum is σ = 13132032202020. Its totient is φ = 13132032202018.
The previous prime is 13132032201979. The next prime is 13132032202033. The reversal of 13132032202019 is 91020223023131.
13132032202019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13132032202019 - 212 = 13132032197923 is a prime.
It is a super-2 number, since 2×131320322020192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13132032201982 and 13132032202000.
It is not a weakly prime, because it can be changed into another prime (13132032232019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566016101009 + 6566016101010.
It is an arithmetic number, because the mean of its divisors is an integer number (6566016101010).
Almost surely, 213132032202019 is an apocalyptic number.
13132032202019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132032202019 is an equidigital number, since it uses as much as digits as its factorization.
13132032202019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 29.
The spelling of 13132032202019 in words is "thirteen trillion, one hundred thirty-two billion, thirty-two million, two hundred two thousand, nineteen".
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