Base | Representation |
---|---|
bin | 10011000111000001011… |
… | …011110010010101011011 |
3 | 11122112121212212211112222 |
4 | 103013001123302111123 |
5 | 133003423314441102 |
6 | 2443140330254255 |
7 | 163606401322535 |
oct | 23070133622533 |
9 | 4575555784488 |
10 | 1313210312027 |
11 | 466a24a93139 |
12 | 19261358738b |
13 | 96ab1c24013 |
14 | 477b9c1c855 |
15 | 2425da6baa2 |
hex | 131c16f255b |
1313210312027 has 2 divisors, whose sum is σ = 1313210312028. Its totient is φ = 1313210312026.
The previous prime is 1313210311993. The next prime is 1313210312107. The reversal of 1313210312027 is 7202130123131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313210312027 - 210 = 1313210311003 is a prime.
It is a super-2 number, since 2×13132103120272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1313210311987 and 1313210312005.
It is not a weakly prime, because it can be changed into another prime (1313210312927) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656605156013 + 656605156014.
It is an arithmetic number, because the mean of its divisors is an integer number (656605156014).
Almost surely, 21313210312027 is an apocalyptic number.
1313210312027 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313210312027 is an equidigital number, since it uses as much as digits as its factorization.
1313210312027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 1313210312027 its reverse (7202130123131), we get a palindrome (8515340435158).
The spelling of 1313210312027 in words is "one trillion, three hundred thirteen billion, two hundred ten million, three hundred twelve thousand, twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •