Base | Representation |
---|---|
bin | 11101110110111110100000… |
… | …000110000000000111011001 |
3 | 122012222012020221202212101222 |
4 | 131312332200012000013121 |
5 | 114203032021104044342 |
6 | 1143144102154221425 |
7 | 36442436336005415 |
oct | 3566764006000731 |
9 | 565865227685358 |
10 | 131321311003097 |
11 | 38930067581476 |
12 | 1288ab49424875 |
13 | 5837714845517 |
14 | 245ddb1bb5d45 |
15 | 102ae7e39eed2 |
hex | 776fa01801d9 |
131321311003097 has 2 divisors, whose sum is σ = 131321311003098. Its totient is φ = 131321311003096.
The previous prime is 131321311003081. The next prime is 131321311003151. The reversal of 131321311003097 is 790300113123131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128774289711376 + 2547021291721 = 11347876^2 + 1595939^2 .
It is a cyclic number.
It is not a de Polignac number, because 131321311003097 - 24 = 131321311003081 is a prime.
It is not a weakly prime, because it can be changed into another prime (131321311003067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65660655501548 + 65660655501549.
It is an arithmetic number, because the mean of its divisors is an integer number (65660655501549).
Almost surely, 2131321311003097 is an apocalyptic number.
It is an amenable number.
131321311003097 is a deficient number, since it is larger than the sum of its proper divisors (1).
131321311003097 is an equidigital number, since it uses as much as digits as its factorization.
131321311003097 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10206, while the sum is 35.
The spelling of 131321311003097 in words is "one hundred thirty-one trillion, three hundred twenty-one billion, three hundred eleven million, three thousand, ninety-seven".
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