Base | Representation |
---|---|
bin | 111101001001101011… |
… | …1001010100111001101 |
3 | 110112222000021101122201 |
4 | 1322103113022213031 |
5 | 4122421230424123 |
6 | 140154520041501 |
7 | 12326156664412 |
oct | 1722327124715 |
9 | 415860241581 |
10 | 131321342413 |
11 | 50769524258 |
12 | 2154b303291 |
13 | c4ca872c51 |
14 | 64dab84109 |
15 | 3638d6c5ad |
hex | 1e935ca9cd |
131321342413 has 4 divisors (see below), whose sum is σ = 131384268000. Its totient is φ = 131258416828.
The previous prime is 131321342407. The next prime is 131321342417. The reversal of 131321342413 is 314243123131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 131321342413 - 217 = 131321211341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131321342417) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31459663 + ... + 31463836.
It is an arithmetic number, because the mean of its divisors is an integer number (32846067000).
Almost surely, 2131321342413 is an apocalyptic number.
It is an amenable number.
131321342413 is a deficient number, since it is larger than the sum of its proper divisors (62925587).
131321342413 is an equidigital number, since it uses as much as digits as its factorization.
131321342413 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62925586.
The product of its digits is 5184, while the sum is 28.
Adding to 131321342413 its reverse (314243123131), we get a palindrome (445564465544).
The spelling of 131321342413 in words is "one hundred thirty-one billion, three hundred twenty-one million, three hundred forty-two thousand, four hundred thirteen".
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