Base | Representation |
---|---|
bin | 1011111100011001000010… |
… | …0111100011111111111011 |
3 | 1201111102100111200210112211 |
4 | 2333012100213203333323 |
5 | 3210124111134022133 |
6 | 43532453351315551 |
7 | 2523523463263003 |
oct | 277062047437773 |
9 | 51442314623484 |
10 | 13132141314043 |
11 | 4203345465854 |
12 | 158111b67bbb7 |
13 | 74348138477b |
14 | 335855a53003 |
15 | 17b8e54c3bcd |
hex | bf1909e3ffb |
13132141314043 has 4 divisors (see below), whose sum is σ = 13134722829120. Its totient is φ = 13129559798968.
The previous prime is 13132141314041. The next prime is 13132141314049. The reversal of 13132141314043 is 34041314123131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13132141314043 - 21 = 13132141314041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13132141313996 and 13132141314014.
It is not an unprimeable number, because it can be changed into a prime (13132141314041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1290749908 + ... + 1290760081.
It is an arithmetic number, because the mean of its divisors is an integer number (3283680707280).
Almost surely, 213132141314043 is an apocalyptic number.
13132141314043 is a deficient number, since it is larger than the sum of its proper divisors (2581515077).
13132141314043 is an equidigital number, since it uses as much as digits as its factorization.
13132141314043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2581515076.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 13132141314043 its reverse (34041314123131), we get a palindrome (47173455437174).
The spelling of 13132141314043 in words is "thirteen trillion, one hundred thirty-two billion, one hundred forty-one million, three hundred fourteen thousand, forty-three".
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