Base | Representation |
---|---|
bin | 1111011110101110111000… |
… | …11011111001110101111011 |
3 | 11110112022120201012100221211 |
4 | 13233113130123321311323 |
5 | 13430213102403420011 |
6 | 200222210330143551 |
7 | 10112255332555030 |
oct | 757273433716573 |
9 | 143468521170854 |
10 | 34041314123131 |
11 | a934927404937 |
12 | 3999527281bb7 |
13 | 15cc10b62b693 |
14 | 859873613387 |
15 | 3e075cceab21 |
hex | 1ef5dc6f9d7b |
34041314123131 has 32 divisors (see below), whose sum is σ = 40458136343040. Its totient is φ = 28023893968896.
The previous prime is 34041314123119. The next prime is 34041314123153. The reversal of 34041314123131 is 13132141314043.
It is not a de Polignac number, because 34041314123131 - 213 = 34041314114939 is a prime.
It is a super-2 number, since 2×340413141231312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 34041314123093 and 34041314123102.
It is not an unprimeable number, because it can be changed into a prime (34041314103131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32634600 + ... + 33661546.
It is an arithmetic number, because the mean of its divisors is an integer number (1264316760720).
Almost surely, 234041314123131 is an apocalyptic number.
34041314123131 is a deficient number, since it is larger than the sum of its proper divisors (6416822219909).
34041314123131 is a wasteful number, since it uses less digits than its factorization.
34041314123131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1027843.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 34041314123131 its reverse (13132141314043), we get a palindrome (47173455437174).
The spelling of 34041314123131 in words is "thirty-four trillion, forty-one billion, three hundred fourteen million, one hundred twenty-three thousand, one hundred thirty-one".
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