Search a number
-
+
1313220002441 is a prime number
BaseRepresentation
bin10011000111000010000…
…000110000001010001001
311122112122120010011022012
4103013002000300022021
5133003433310034231
62443141314105305
7163606546562504
oct23070200601211
94575576104265
101313220002441
11466a2a501746
1219261687b235
1396ab3c379a9
14477bb22213b
152425e832e2b
hex131c2030289

1313220002441 has 2 divisors, whose sum is σ = 1313220002442. Its totient is φ = 1313220002440.

The previous prime is 1313220002417. The next prime is 1313220002459. The reversal of 1313220002441 is 1442000223131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1147424450041 + 165795552400 = 1071179^2 + 407180^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313220002441 - 210 = 1313220001417 is a prime.

It is a super-2 number, since 2×13132200024412 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1313220007441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656610001220 + 656610001221.

It is an arithmetic number, because the mean of its divisors is an integer number (656610001221).

Almost surely, 21313220002441 is an apocalyptic number.

It is an amenable number.

1313220002441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313220002441 is an equidigital number, since it uses as much as digits as its factorization.

1313220002441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1313220002441 its reverse (1442000223131), we get a palindrome (2755220225572).

The spelling of 1313220002441 in words is "one trillion, three hundred thirteen billion, two hundred twenty million, two thousand, four hundred forty-one".