Base | Representation |
---|---|
bin | 111101001001101101… |
… | …0110111001001011001 |
3 | 110112222002002121122211 |
4 | 1322103122313021121 |
5 | 4122422002430012 |
6 | 140154552515121 |
7 | 12326201141134 |
oct | 1722332671131 |
9 | 415862077584 |
10 | 131322311257 |
11 | 5076a026155 |
12 | 2154b6abaa1 |
13 | c4cab21c27 |
14 | 64dad5721b |
15 | 3638eae6a7 |
hex | 1e936b7259 |
131322311257 has 2 divisors, whose sum is σ = 131322311258. Its totient is φ = 131322311256.
The previous prime is 131322311201. The next prime is 131322311279. The reversal of 131322311257 is 752113223131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113283403776 + 18038907481 = 336576^2 + 134309^2 .
It is an emirp because it is prime and its reverse (752113223131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131322311257 - 27 = 131322311129 is a prime.
It is not a weakly prime, because it can be changed into another prime (131322311557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65661155628 + 65661155629.
It is an arithmetic number, because the mean of its divisors is an integer number (65661155629).
Almost surely, 2131322311257 is an apocalyptic number.
It is an amenable number.
131322311257 is a deficient number, since it is larger than the sum of its proper divisors (1).
131322311257 is an equidigital number, since it uses as much as digits as its factorization.
131322311257 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7560, while the sum is 31.
Adding to 131322311257 its reverse (752113223131), we get a palindrome (883435534388).
The spelling of 131322311257 in words is "one hundred thirty-one billion, three hundred twenty-two million, three hundred eleven thousand, two hundred fifty-seven".
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