Base | Representation |
---|---|
bin | 10011000111000010001… |
… | …100101001010010000000 |
3 | 11122112122202222112210100 |
4 | 103013002030221102000 |
5 | 133003440104320000 |
6 | 2443141505002400 |
7 | 163606615225551 |
oct | 23070214512200 |
9 | 4575582875710 |
10 | 1313223120000 |
11 | 466a31240a40 |
12 | 192617923400 |
13 | 96ab47899bc |
14 | 477bb7d4328 |
15 | 2425ec4ba00 |
hex | 131c2329480 |
1313223120000 has 480 divisors, whose sum is σ = 5151477062160. Its totient is φ = 318355200000.
The previous prime is 1313223119959. The next prime is 1313223120019. The reversal of 1313223120000 is 213223131.
1313223120000 is a `hidden beast` number, since 1 + 31 + 322 + 312 + 0 + 0 + 0 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (480).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 7837095 + ... + 8002905.
Almost surely, 21313223120000 is an apocalyptic number.
1313223120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1313223120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2575738531080).
1313223120000 is an abundant number, since it is smaller than the sum of its proper divisors (3838253942160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313223120000 is a wasteful number, since it uses less digits than its factorization.
1313223120000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165862 (or 165832 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 1313223120000 its reverse (213223131), we get a palindrome (1313436343131).
It can be divided in two parts, 13132 and 23120000, that added together give a palindrome (23133132).
The spelling of 1313223120000 in words is "one trillion, three hundred thirteen billion, two hundred twenty-three million, one hundred twenty thousand".
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