13132344001442 has 4 divisors (see below), whose sum is σ = 19698516002166. Its totient is φ = 6566172000720.

The previous prime is 13132344001379. The next prime is 13132344001459. The reversal of 13132344001442 is 24410044323131.

13132344001442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12888595424761 + 243748576681 = 3590069^2 + 493709^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13132344001399 and 13132344001408.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3283086000359 + ... + 3283086000362.

Almost surely, 2^{13132344001442} is an apocalyptic number.

13132344001442 is a deficient number, since it is larger than the sum of its proper divisors (6566172000724).

13132344001442 is an equidigital number, since it uses as much as digits as its factorization.

13132344001442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6566172000723.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13132344001442 its reverse (24410044323131), we get a palindrome (37542388324573).

The spelling of 13132344001442 in words is "thirteen trillion, one hundred thirty-two billion, three hundred forty-four million, one thousand, four hundred forty-two".