Base | Representation |
---|---|
bin | 11000011101100000… |
… | …01000100011000001 |
3 | 1020220012221002021001 |
4 | 30032300020203001 |
5 | 203343343311313 |
6 | 10011040532001 |
7 | 643301364616 |
oct | 141660104301 |
9 | 36805832231 |
10 | 13132400833 |
11 | 5629997132 |
12 | 2666021001 |
13 | 131394b1a6 |
14 | 8c819250d |
15 | 51cda6add |
hex | 30ec088c1 |
13132400833 has 2 divisors, whose sum is σ = 13132400834. Its totient is φ = 13132400832.
The previous prime is 13132400797. The next prime is 13132400863. The reversal of 13132400833 is 33800423131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7284281104 + 5848119729 = 85348^2 + 76473^2 .
It is an emirp because it is prime and its reverse (33800423131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13132400833 - 233 = 4542466241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13132400863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566200416 + 6566200417.
It is an arithmetic number, because the mean of its divisors is an integer number (6566200417).
Almost surely, 213132400833 is an apocalyptic number.
It is an amenable number.
13132400833 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132400833 is an equidigital number, since it uses as much as digits as its factorization.
13132400833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13132400833 its reverse (33800423131), we get a palindrome (46932823964).
The spelling of 13132400833 in words is "thirteen billion, one hundred thirty-two million, four hundred thousand, eight hundred thirty-three".
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