Base | Representation |
---|---|
bin | 100111001000110… |
… | …0111101110110001 |
3 | 10101112002121101211 |
4 | 1032101213232301 |
5 | 10142142221113 |
6 | 334151200121 |
7 | 44354241655 |
oct | 11621475661 |
9 | 3345077354 |
10 | 1313242033 |
11 | 6143221a4 |
12 | 307976041 |
13 | 17c0c33bc |
14 | c65aaa65 |
15 | 7a458b3d |
hex | 4e467bb1 |
1313242033 has 2 divisors, whose sum is σ = 1313242034. Its totient is φ = 1313242032.
The previous prime is 1313241997. The next prime is 1313242037. The reversal of 1313242033 is 3302423131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1210483264 + 102758769 = 34792^2 + 10137^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313242033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313241995 and 1313242013.
It is not a weakly prime, because it can be changed into another prime (1313242037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656621016 + 656621017.
It is an arithmetic number, because the mean of its divisors is an integer number (656621017).
Almost surely, 21313242033 is an apocalyptic number.
It is an amenable number.
1313242033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313242033 is an equidigital number, since it uses as much as digits as its factorization.
1313242033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 22.
The square root of 1313242033 is about 36238.6814467635. The cubic root of 1313242033 is about 1095.0860792891.
Adding to 1313242033 its reverse (3302423131), we get a palindrome (4615665164).
The spelling of 1313242033 in words is "one billion, three hundred thirteen million, two hundred forty-two thousand, thirty-three".
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