13132431130111 has 4 divisors (see below), whose sum is σ = 13132785724000. Its totient is φ = 13132076536224.

The previous prime is 13132431130073. The next prime is 13132431130129. The reversal of 13132431130111 is 11103113423131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13132431130111 - 2⁹ = 13132431129599 is a prime.

It is a super-2 number, since 2×13132431130111² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13132431130151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177241386 + ... + 177315463.

It is an arithmetic number, because the mean of its divisors is an integer number (3283196431000).

Almost surely, 2^{13132431130111} is an apocalyptic number.

13132431130111 is a deficient number, since it is larger than the sum of its proper divisors (354593889).

13132431130111 is an equidigital number, since it uses as much as digits as its factorization.

13132431130111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354593888.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 13132431130111 its reverse (11103113423131), we get a palindrome (24235544553242).

The spelling of 13132431130111 in words is "thirteen trillion, one hundred thirty-two billion, four hundred thirty-one million, one hundred thirty thousand, one hundred eleven".