1313244103001 has 4 divisors (see below), whose sum is σ = 1313682000000. Its totient is φ = 1312806206004.

The previous prime is 1313244102983. The next prime is 1313244103021. The reversal of 1313244103001 is 1003014423131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1313244103001 is a prime.

It is a super-2 number, since 2×1313244103001² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1313244103021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218944001 + ... + 218949998.

It is an arithmetic number, because the mean of its divisors is an integer number (328420500000).

Almost surely, 2^{1313244103001} is an apocalyptic number.

It is an amenable number.

1313244103001 is a deficient number, since it is larger than the sum of its proper divisors (437896999).

1313244103001 is an equidigital number, since it uses as much as digits as its factorization.

1313244103001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437896998.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1313244103001 its reverse (1003014423131), we get a palindrome (2316258526132).

The spelling of 1313244103001 in words is "one trillion, three hundred thirteen billion, two hundred forty-four million, one hundred three thousand, one".