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1313244102983 is a prime number
BaseRepresentation
bin10011000111000011011…
…100101100000101000111
311122112201020110121000212
4103013003130230011013
5133004010442243413
62443143534430035
7163610261460461
oct23070334540507
94575636417025
101313244102983
11466a4207284a
1219262296231b
1396ab8c25677
14477c04d7131
15242619e3ca8
hex131c372c147

1313244102983 has 2 divisors, whose sum is σ = 1313244102984. Its totient is φ = 1313244102982.

The previous prime is 1313244102953. The next prime is 1313244103021. The reversal of 1313244102983 is 3892014423131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1313244102983 - 240 = 213732475207 is a prime.

It is a super-2 number, since 2×13132441029832 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1313244102983.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313244102953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656622051491 + 656622051492.

It is an arithmetic number, because the mean of its divisors is an integer number (656622051492).

Almost surely, 21313244102983 is an apocalyptic number.

1313244102983 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313244102983 is an equidigital number, since it uses as much as digits as its factorization.

1313244102983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 124416, while the sum is 41.

The spelling of 1313244102983 in words is "one trillion, three hundred thirteen billion, two hundred forty-four million, one hundred two thousand, nine hundred eighty-three".