Base | Representation |
---|---|
bin | 10011000111000011011… |
… | …100101100000101011000 |
3 | 11122112201020110121001111 |
4 | 103013003130230011120 |
5 | 133004010442244000 |
6 | 2443143534430104 |
7 | 163610261460514 |
oct | 23070334540530 |
9 | 4575636417044 |
10 | 1313244103000 |
11 | 466a42072865 |
12 | 192622962334 |
13 | 96ab8c2568b |
14 | 477c04d7144 |
15 | 242619e3cba |
hex | 131c372c158 |
1313244103000 has 128 divisors (see below), whose sum is σ = 3204829555200. Its totient is φ = 503110656000.
The previous prime is 1313244102983. The next prime is 1313244103021. The reversal of 1313244103000 is 3014423131.
It is a super-2 number, since 2×13132441030002 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2788636 + ... + 3225364.
It is an arithmetic number, because the mean of its divisors is an integer number (25037730900).
Almost surely, 21313244103000 is an apocalyptic number.
1313244103000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1313244103000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1602414777600).
1313244103000 is an abundant number, since it is smaller than the sum of its proper divisors (1891585452200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313244103000 is a wasteful number, since it uses less digits than its factorization.
1313244103000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 436878 (or 436864 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 1313244103000 its reverse (3014423131), we get a palindrome (1316258526131).
It can be divided in two parts, 131324 and 4103000, that added together give a palindrome (4234324).
The spelling of 1313244103000 in words is "one trillion, three hundred thirteen billion, two hundred forty-four million, one hundred three thousand".
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