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1313253433 is a prime number
BaseRepresentation
bin100111001000110…
…1010100000111001
310101112010012001001
41032101222200321
510142143102213
6334151325001
744354320132
oct11621524071
93345105031
101313253433
1161432a818
12307980761
1317c0c864b
14c65b0c89
157a45c1dd
hex4e46a839

1313253433 has 2 divisors, whose sum is σ = 1313253434. Its totient is φ = 1313253432.

The previous prime is 1313253421. The next prime is 1313253443. The reversal of 1313253433 is 3343523131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 704743209 + 608510224 = 26547^2 + 24668^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1313253433 is a prime.

It is not a weakly prime, because it can be changed into another prime (1313253413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656626716 + 656626717.

It is an arithmetic number, because the mean of its divisors is an integer number (656626717).

Almost surely, 21313253433 is an apocalyptic number.

It is an amenable number.

1313253433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313253433 is an equidigital number, since it uses as much as digits as its factorization.

1313253433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9720, while the sum is 28.

The square root of 1313253433 is about 36238.8387369132. The cubic root of 1313253433 is about 1095.0892480233.

Adding to 1313253433 its reverse (3343523131), we get a palindrome (4656776564).

The spelling of 1313253433 in words is "one billion, three hundred thirteen million, two hundred fifty-three thousand, four hundred thirty-three".